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From section 3.6 the radiation impedance matrix for a
cylindrical pipe terminated in an infinite baffle is:
![$\displaystyle Z_{nm} =
\frac{\rho c}{S}
\int\limits_0^{\frac{\pi}{2}} \sin{\phi}
D_n(\sin{\phi}) D_m(\sin{\phi}) d \phi$](img360.png) |
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![$\displaystyle + \frac{i\rho c}{S}
\int\limits_0^\infty \cosh{\xi}
D_n(\cosh{\xi}) D_m(\cosh{\xi}) d \xi$](img436.png) |
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|
(4.1) |
where
![\begin{displaymath}
D_n(\tau) = \frac{-\sqrt{2} \tau J_1(\tau k R)}
{(\frac{\gamma_n}{kR})^2 - \tau^2}.
\end{displaymath}](img350.png) |
(4.2) |
Jonathan Kemp
2003-03-24